Ŀ

գҪıйص䡣
һrepeat (0<repeat<10)repeat㣺
2 m  n(m<=n)ʽ 1/m + 1/(m+1) + 1/(m+2) + ...... + 1/nֵʱ3λС
ʾΪ˵

3        (repeat=3)
5 15     (1/5+1/6+1/7+...+1/15)
10 20    (1/10+1/11+1/12+...+1/20)
1 3      (1+1/2+1/3)

sum = 1.235
sum = 0.769
sum = 1.833



#include <stdio.h>
int main(void)
{   
    int i, m, n;
    int repeat, ri;
    double sum;

    scanf("%d", &repeat);
    for(ri = 1; ri <= repeat; ri++){
        scanf("%d%d", &m, &n);	
/*---------*/
        printf("sum = %.3f\n", sum);
    }    	 
}

