Ŀ

գҪıйص䡣
һrepeat (0<repeat<10)repeat㣺
 m  n(m<=n) sum = m*m1/m(m+1)*(m+1)1/(m+1)(m+2)*(m+2)1/(m+2)......n*n1/n6λС
ʾΪ˵

3        (repeat=3)
1 2      (m=1,n=2)
2 5      (m=2,n=5)
5 10     (m=5,n=10)

sum = 6.500000
sum = 55.283333
sum = 355.845635



#include <stdio.h>
int main(void)
{   
    int i, m, n;
    int repeat, ri;
    double sum;

    scanf("%d",&repeat);
    for(ri = 1; ri <= repeat; ri++){
        scanf("%d%d", &m, &n);
/*---------*/
         printf("sum = %.6f\n", sum);
    }
}

